<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<title>Title</title>
</head>
<body>
<script type="text/javascript">
//两个数组求笛卡尔积
/*let arr1 = ["a","b","c"]
let arr2 = ["1","2","3"]
let arr3 = ["x","y","z"]
// a_1 a_2 a_3 b_1 .......
//arr1.forEach(function(e1){}) e1就是arr1数组每次遍历的元素
//如果数组的个数不确定,这种方式便不可以取
arr1.forEach(e1=>{
arr2.forEach(e2=>{
arr3.forEach(e3=>{
console.log(e1+"_"+e2+"_"+e3)
})
})
})*/
// es6 的一个方法 --- reduce 数组元素的“累加” 拿前一个元素和后面的元素依次进行计算
/*let arr1 = ["a","b","c","d"]
let arr2 = ["1","2","3","4"]
//["a_1","a_2","a_3","b_1",.....]
let arr3 = ["x","y","z"]
let arr4 = ["A","B","C"]
let arr = [arr1,arr2,arr3,arr4]
//arr.reduce(callback(pre,curr),init) pre是上一次的计算结果,curr当前元素 init是初始值
//如果设置了初始值,则第一次是拿初始值和第一个元素进行计算
//如果没有设置初始值,则第一次是拿第一个元素和第二个元素进行计算
let res = arr.reduce((pre,cur)=>{
//pre = ["a","b","c"]
//cur = ["1","2","3"]
let result = [];//作为每次计算的结果,作为下一次结算的pre
pre.forEach(e1=>{
cur.forEach(e2=>{
result.push(e1+"_"+e2)
})
})
return result;
})
console.log(res)*/
//模拟真实数据
let skuProperties = [
{
"specName": "肤色",
"options": ["黑色", "黄色"]
},
{
"specName": "年龄",
"options": ["萝莉", "御姐"]
},{
"specName": "体型",
"options": ["腿长1米8", "身高1米5"]
}]
let res = skuProperties.reduce((pre,cur)=>{
let result = [];
pre.forEach(e1=>{ // e1 {}
//cur {"specName":"肤色",options:["黑色","黄色"]}
//sku_index 位置 索引值 0_0_0
e1.sku_index = (e1.sku_index||'')+"_"; // e1 = {sku_index:'_'}
for(let i=0;i<cur.options.length;i++){
let e2 = cur.options[i]; //["黑色","黄色"]
let temp = {}
Object.assign(temp,e1);
temp[cur.specName] = e2;
temp.sku_index += i;//temp = {"肤色":"黑色",sku_index:'_0'}
result.push(temp);
}
})
return result;
},[{}])
//添加价格
res.forEach(e1=>{
e1.price = 0;
e1.availableStock = 0;
e1.sku_index = e1.sku_index.substring(1);
})
console.log(res)
/*let init = [{sku_index:_}]
let zero = [
{"肤色":"黑色",sku_index:_0},
{"肤色":"黄色",sku_index:1}
]
let first = [
{"肤色":"黑色","年龄":"萝莉",sku_index:_0_0},
{"肤色":"黑色","年龄":"御姐"},
{"肤色":"黄色","年龄":"萝莉"},
{"肤色":"黄色","年龄":"御姐"}
]*/
</script>
</body>
</html>
通过F12控制台查看
版权声明:本文内容由互联网用户自发贡献,该文观点仅代表作者本人。本站仅提供信息存储空间服务,不拥有所有权,不承担相关法律责任。如发现本站有涉嫌侵权/违法违规的内容, 请发送邮件至 举报,一经查实,本站将立刻删除。
文章由极客之音整理,本文链接:https://www.bmabk.com/index.php/post/75143.html